Basic Math Examples

\frac{3}{8} + \frac{2}{7}

$\frac{3}{8} + \frac{2}{7}$

Step 1

To write

\frac{3}{8}

$\frac{3}{8}$ as a fraction with a common denominator, multiply by

\frac{7}{7}

$\frac{7}{7}$ .

\frac{3}{8} \cdot \frac{7}{7} + \frac{2}{7}

$\frac{3}{8} \cdot \frac{7}{7} + \frac{2}{7}$

Step 2

To write

\frac{2}{7}

$\frac{2}{7}$ as a fraction with a common denominator, multiply by

\frac{8}{8}

$\frac{8}{8}$ .

\frac{3}{8} \cdot \frac{7}{7} + \frac{2}{7} \cdot \frac{8}{8}

$\frac{3}{8} \cdot \frac{7}{7} + \frac{2}{7} \cdot \frac{8}{8}$

Step 3

Write each expression with a common denominator of

56

$56$ , by multiplying each by an appropriate factor of

1

$1$ .

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Step 3.1

Multiply

\frac{3}{8}

$\frac{3}{8}$ by

\frac{7}{7}

$\frac{7}{7}$ .

\frac{3 \cdot 7}{8 \cdot 7} + \frac{2}{7} \cdot \frac{8}{8}

$\frac{3 \cdot 7}{8 \cdot 7} + \frac{2}{7} \cdot \frac{8}{8}$

Step 3.2

Multiply

8

$8$ by

7

$7$ .

\frac{3 \cdot 7}{56} + \frac{2}{7} \cdot \frac{8}{8}

$\frac{3 \cdot 7}{56} + \frac{2}{7} \cdot \frac{8}{8}$

Step 3.3

Multiply

\frac{2}{7}

$\frac{2}{7}$ by

\frac{8}{8}

$\frac{8}{8}$ .

\frac{3 \cdot 7}{56} + \frac{2 \cdot 8}{7 \cdot 8}

$\frac{3 \cdot 7}{56} + \frac{2 \cdot 8}{7 \cdot 8}$

Step 3.4

Multiply

7

$7$ by

8

$8$ .

\frac{3 \cdot 7}{56} + \frac{2 \cdot 8}{56}

$\frac{3 \cdot 7}{56} + \frac{2 \cdot 8}{56}$

\frac{3 \cdot 7}{56} + \frac{2 \cdot 8}{56}

$\frac{3 \cdot 7}{56} + \frac{2 \cdot 8}{56}$

Step 4

Combine the numerators over the common denominator.

\frac{3 \cdot 7 + 2 \cdot 8}{56}

$\frac{3 \cdot 7 + 2 \cdot 8}{56}$

Step 5

Simplify the numerator.

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Step 5.1

Multiply

3

$3$ by

7

$7$ .

\frac{21 + 2 \cdot 8}{56}

$\frac{21 + 2 \cdot 8}{56}$

Step 5.2

Multiply

2

$2$ by

8

$8$ .

\frac{21 + 16}{56}

$\frac{21 + 16}{56}$

Step 5.3

Add

21

$21$ and

16

$16$ .

\frac{37}{56}

$\frac{37}{56}$

\frac{37}{56}

$\frac{37}{56}$

Step 6

The result can be shown in multiple forms.

Exact Form:

\frac{37}{56}

$\frac{37}{56}$

Decimal Form:

0.66071428 \dots

$0.66071428 \dots$